What a load really sees
Thévenin is a statement about terminal behavior, not a trick for simplifying resistor drawings.
- Define a two-terminal port and distinguish internal topology from external behavior.
- Derive the affine terminal relation V = VTH − RTH·I for a linear resistive network.
- Connect open-circuit voltage, short-circuit current and equivalent resistance.
- State clearly when the theorem applies and when a simple resistance is not sufficient.
If a load is connected to a complicated linear circuit, how much of the internal circuit does the load actually need to know?
The answer is the organising idea of this chapter: for a two-terminal linear network, the load only needs the terminal voltage–current relation. Thévenin and Norton are two compact ways of writing that same relation.
01.1Begin with the two terminals
Take any network made of linear elements and independent or dependent sources, and hide it inside a box. Leave only two terminals accessible. From the outside, the internal drawing is no longer observable directly. A load can only establish a current at the port and observe the resulting terminal voltage.
This shift in viewpoint is the useful content of Thévenin's theorem. The theorem is not primarily a recipe for replacing three resistors by one resistor. It says that, for a linear one-port in a given regime, the external world can be made insensitive to the internal complexity if we preserve the port relation.
Figure 1.1 — What the external world can observe
The internal network may be arbitrarily complicated. At the port, the load only exchanges a current I and observes a voltage V = VA − VB.
Historically, equivalent-source ideas appeared before electronic engineering existed as a discipline. Helmholtz obtained a voltage-source equivalent in 1853; Thévenin published an equivalent result independently in 1883 in the context of telegraph networks. The recurring engineering problem was already familiar: how can a large network be replaced by the smallest model that predicts what happens at its terminals?
01.2Why the terminal law must be affine
Define the port voltage as V = VA − VB. Let I be positive when the hidden network delivers current to the external load. Because the network is linear, superposition lets us separate two contributions to the port voltage.
First set I = 0. The port is open, so the voltage that remains is the open-circuit voltage VOC. Now zero the independent sources and impose a current at the port. In a linear network, the resulting voltage change must be proportional to that imposed current. With our current convention, that proportionality appears as a negative slope.
Figure 1.2 — The terminal law as a straight line
VTH is the voltage intercept, ISC is the current intercept, and the magnitude of the slope is RTH.
The familiar drawing — an ideal voltage source in series with a resistor — is therefore not the theorem itself. It is simply the smallest circuit that has the same intercept and the same slope in the V–I plane.
01.3Open circuit and short circuit identify two points on the same line
Two operating points are especially useful. With an open circuit, I = 0, so the terminal voltage is VTH. With an ideal short circuit, V = 0, so the delivered current is VTH/RTH whenever RTH is finite and non-zero.
Figure 1.3a — Thévenin form
The port model emphasizes the open-circuit voltage VTH and series resistance RTH.
Figure 1.3b — Norton form
The same port law can emphasize the short-circuit current IN and parallel resistance RN.
This is the cleanest way to see why Thévenin and Norton are the same model. One emphasizes the voltage intercept; the other emphasizes the current intercept. Both reproduce the same straight terminal characteristic.
01.4Worked example: a source is only “stiff” relative to its load
Suppose a sensor interface is represented by VTH = 5.0 V and RTH = 100 Ω, and it drives RL = 900 Ω. Calling it merely a “5 V source” hides the fact that the source itself participates in the voltage division.
Figure 1.4 — The loaded 5 V source
The same current IL flows through RTH and RL. VL is defined with positive polarity at the load’s upper terminal.
The load receives only 90% of the open-circuit voltage. The important quantity is therefore the ratio RL/RTH, not the label “high impedance” by itself.
01.5Where the simple model stops
The theorem survives far beyond elementary resistor circuits, but the object that replaces RTH changes. In sinusoidal steady state, it becomes a complex impedance ZTH(ω). Around a nonlinear device bias point, a local small-signal linearization can create a useful incremental equivalent.
A single fixed VTH and RTH, however, cannot reproduce a strongly nonlinear V–I curve over a wide operating range. The model is useful because it preserves the behaviour needed for a specific question, not because it reproduces every internal physical detail.
01.6Check before moving on
Three short questions
- What does a load actually “see” of a hidden linear one-port?
- Why do Thévenin and Norton describe the same external behaviour?
- If RL = 9RTH, what fraction of the open-circuit voltage appears across the load?