Poles, zeros & characteristic frequencies
Introduce the generalized complex frequency s=σ+jω from exponential trial functions rather than memorizing pole/zero vocabulary. Derive H(s)=B(s)/A(s) for constant-coefficient LTI differential equations, connect denominator roots to natural modes and numerator roots to transfer zeros, recover H(jω) on the imaginary axis, and interpret first-order pole/zero locations, characteristic frequencies, stability caveats and imperfect pole-zero cancellation before any Bode slope rules.
- Derive the polynomial response of a constant-coefficient differential operator to e^{st}.
- Define H(s)=B(s)/A(s) from the input/output differential equation without requiring Laplace as the starting point.
- Define poles as roots of A(s) and zeros as roots of B(s), after common-factor reduction appropriate to the transfer description.
- Explain why poles coincide with natural exponential modes of the homogeneous system.
- Explain what a transfer zero means for the declared input/output pair and why it depends on that pair.
- Recover the sinusoidal frequency response as H(jω) when the steady-state evaluation is meaningful.
- Relate a first-order pole at s=−ω₀ to the characteristic angular frequency ω₀ of 1/(1+s/ω₀).
- Relate a zero at the origin to first-order high-pass behavior and state the limits of ideal pole-zero cancellation.
Chapter 02 described the exact magnitude and phase of H(jω), but it still treated each formula as a finished expression. We now want to expose the structure inside that expression: which mathematical features set characteristic frequencies, create attenuation or transmission zeros, and reveal natural modes of the underlying differential equation?
The answer is the pole-zero structure of a more general function H(s).
03.1Why introduce s=σ+jω?
Sinusoids use the special complex exponential ejωt. A constant-coefficient linear differential operator is equally simple on the more general exponential
because
The real part σ controls exponential growth or decay; the imaginary part ω controls oscillation. Setting σ=0 returns the sinusoidal axis used in AC-01 and chapters 01–02 of AC-02.
03.2Derive H(s) from the same differential equation
Write the declared input/output relation as
with
Use an exponential trial input x(t)=Xest and seek a particular response y(t)=Yest. The common exponential cancels:
so, wherever the ratio is defined,
This is the generalized exponential input/output ratio. A later Laplace treatment gives the familiar transfer-function interpretation under its own assumptions, including treatment of initial conditions. We do not need that machinery to identify the algebraic pole-zero structure here.
03.3Poles come from the homogeneous natural modes
With the external input set to zero, the homogeneous equation is
Try yh=Cept. Then
The roots p of the denominator polynomial are therefore the exponential natural-mode exponents. Those same roots are poles of the reduced transfer ratio H(s)=B(s)/A(s).
For ordinary continuous-time rational systems, a pole with negative real part corresponds to a decaying exponential mode; zero real part gives a non-decaying ideal mode; positive real part gives a growing mode.
03.4Zeros belong to the declared input/output transfer
A transfer zero z is a root of the reduced numerator:
For the corresponding exponential excitation, the ideal transfer ratio is zero. A zero on the imaginary axis, z=jωz, means the selected output vanishes at that sinusoidal frequency in the ideal model.
Zeros are strongly tied to the chosen input and output. The same physical network can have different zeros when a different node voltage or branch current is declared as the output.
03.5Recover the sinusoidal response on the imaginary axis
The sinusoidal frequency response is obtained by evaluating the generalized function at
when that evaluation corresponds to a meaningful bounded steady-state experiment. Geometrically, the real-frequency sweep walks along the imaginary axis of the s-plane.
Figure 3.1 — How does a pole set a frequency scale?
The one question is: why does the pole s=−ω₀ make ω₀ special when H is observed on the jω axis?
Frequency response evaluates H(s) on the imaginary axis. For a factor 1/(s+ω₀), the denominator at s=jω is the vector from the pole −ω₀ to the point jω. Its size changes character when ω becomes comparable to ω₀.
This is why pole location influences magnitude and phase even when the pole itself is not on the jω axis: the distance and angle from each evaluation point jω to the pole change with ω.
03.6First-order low-pass: one pole sets the characteristic frequency
The RC low-pass can be written
The denominator vanishes at
so there is one real negative pole. On the sinusoidal axis,
When ω≪ω₀, the imaginary term is small compared with ω₀. When ω≈ω₀, both are comparable. When ω≫ω₀, the jω term dominates. The characteristic frequency is therefore visible directly from the pole scale—before any Bode rule is memorized.
03.7First-order high-pass: add a zero at the origin
The complementary RC high-pass response is
It has the same pole
and one zero at
The zero at the origin forces
so DC is rejected. At high frequency the numerator and denominator have the same leading dependence on s, so the ratio tends to one.
Low-pass and high-pass therefore share one natural pole but differ by their transfer zeros and numerator structure.
03.8Factor form makes structure explicit
A rational transfer function can often be written in factored form
or, for real first-order characteristic frequencies, in normalized factors such as
This form will make Bode reasoning systematic in chapter 04 because multiplication of factors becomes addition of logarithmic magnitudes and phase contributions. But chapter 04 will derive those rules; chapter 03 uses factorization only to expose structure.
03.9Pole-zero cancellation is an ideal algebraic statement
Suppose an unreduced expression contains a common factor:
The external transfer ratio reduces algebraically to
For that exact reduced input/output ratio, s=−a is not a pole. But two cautions are essential.
First, a physical implementation may contain an internal mode associated with the canceled dynamics even though that mode is invisible in the chosen external transfer under ideal assumptions. Second, real component tolerances make exact pole-zero cancellation fragile: a near-cancellation can leave a residual feature.
Therefore “the algebra canceled” is not evidence that all internal energy storage or all physical sensitivity disappeared.
03.10Mastery exercises
- Show that Dkest=skest.
- For τ dy/dt+y=Kx, derive H(s), identify its pole, and recover H(jω).
- For the RC high-pass, identify its pole and zero and explain the DC limit from the zero.
- A pole is at p=−2000 s⁻¹. What characteristic angular frequency and hertz frequency does it define?
- What does a pole with positive real part imply about a natural exponential mode?
- Why can two outputs of the same physical network have different zeros?
- Reduce (s+10)/[(s+10)(s+100)] and explain what the reduction does—and does not—prove physically.
- For H(s)=5(1+s/1000)/[(1+s/100)(1+s/10000)], list the finite poles, zero and low-frequency value without drawing a Bode plot.
Solutions
1. Repeated differentiation multiplies est by s each time.
2. H(s)=K/(1+sτ)=K/τ divided by (s+1/τ); pole p=−1/τ. Set s=jω to recover H(jω)=K/(1+jωτ).
3. HHP(s)=s/(s+ω₀): zero z=0, pole p=−ω₀. The zero forces H(0)=0.
4. ω₀=2000 rad/s and f₀=2000/(2π)=318.31 Hz.
5. The corresponding natural mode contains eRe(p)t with positive exponent and grows rather than decays.
6. A zero describes cancellation between the declared input and one particular output; changing the output changes the transfer numerator.
7. The reduced external ratio is 1/(s+100). Exact cancellation removes −10 from that ratio, but does not by itself prove that a physical internal mode or tolerance sensitivity is absent.
8. Poles at −100 and −10000 rad/s, zero at −1000 rad/s, and H(0)=5.
Chapter 04 will derive Bode magnitude and phase rules from these factors. Slopes and corner-frequency contributions will appear as consequences of logarithms and asymptotic limits, not as a memorized chart.